-5t^2+12,2t-3,721=0

Solution for -5t^2+12,2t-3,721=0 equation:

-5t^2+12.2t-3.721=0

a = -5; b = 12.2; c = -3.721;
Δ = b2-4ac
Δ = 12.22-4·(-5)·(-3.721)
Δ = 74.42
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12.2)-\sqrt{74.42}}{2*-5}=\frac{-12.2-\sqrt{74.42}}{-10}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12.2)+\sqrt{74.42}}{2*-5}=\frac{-12.2+\sqrt{74.42}}{-10}
$